Re: [xsl] Identity transformation (without using xsl:copy)

["J.Pietschmann" <j3322ptm at yahoo dot de>]

Roger L. Costello wrote:
> If this is the start document:
> 
> <?xml version="1.0"?>
> <j:juicers xmlns:j="http://www.juicers.org";>
>      <j:juicer id="omega">
...
> Then this should be the result document:
> 
> <?xml version="1.0"?>
> <j:JUICERS xmlns:j="http://www.juicers.org";>
>      <j:JUICER id="omega">
...
> If I could use <xsl:element> then I could easily accomplish this
> transformation.  However, it escapes me how to do it if I am forced to
> use <xsl:copy>.  

Check whether this can be modified to fit your needs. Don't count
on namespace prefixes being preserved.
   <xsl:template match="*">
       <xsl:element name="{local-name(.)}" namespace={namespace-uri(.)}>
           <xsl:for-each select="@*">
               <xsl:attribute name="{local-name(.)} namespace={namespace-uri(.)}">
                   <xsl:value-of select="."/>
               </xsl:attribute>
           </xsl:for-each>
           <xsl:apply-templates/>
       </xsl:element>
   </xsl:template>

J.Pietschmann


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list