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Re: which file to include or copy or copy-of
- From: Jörg Heinicke <joerg dot heinicke at gmx dot de>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Thu, 15 Nov 2001 00:17:20 +0100
- Subject: Re: [xsl] which file to include or copy or copy-of
- References: <000701c16d38$e0c9c400$e800005a@Pau>
- Reply-to: xsl-list at lists dot mulberrytech dot com
> //// <xsl:include href="THE ACTIVE FILE=1"/> or
> //// <xsl:copy select="THE ACTIVE FILE=1"/> or
> //// <xsl:copy-of select="THE ACTIVE FILE=1"/>
<xsl:include> is for including other stylesheets and so the templates in the
current one. If you really only want to copy the content of the other
xml-files to the output-tree, try <xsl:copy-of
select="document('filename')"/>. A way with more influence is to store the
document in a variable and use it as normal node-sets:
<xsl:template match="/">
<xsl:variable name="file" select="document('filename')"/>
<xsl:for-each select="$file/rootelement/element">
<!-- and so on -->
</xsl:for-each>
</xsl:template>
Hope this helps,
Joerg
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