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Re: how to test the existence of a file on the hard disk ?
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: Re: [xsl] how to test the existence of a file on the hard disk ?
- From: "Paulo Henrique S. Bermejo" <bermejo at eps dot ufsc dot br>
- Date: Fri, 31 Aug 2001 10:01:54 -0300
- References: <C1256AB9.00328DFD.00@frmta01.netfr.alcatel.fr>
- Reply-To: xsl-list at lists dot mulberrytech dot com
Stephane,
Maybe I can to help.
Exist a function XPath that become possible to acess documents. The name is
"document(file)".
This case, to acess a document in a variable you should:
<xsl:variable name="meu_documento_xml"
select="document(path/document.xml)"/>
I don't know as you can to certify if file exists, but I think that is begin
good.
Cheers,
Paulo Henrique Bermejo
University Federal of Santa Catarina - Florianópolis/SC
Brazil
----- Original Message -----
From: Stephane.Le-Deaut@alcatel.fr
To: xsl-list@lists.mulberrytech.com
Sent: Friday, August 31, 2001 6:12 AM
Subject: [xsl] how to test the existence of a file on the hard disk ?
Hello all,
I want to check if a file exists on the hard disk with XSL.
I tried this way without success :
<xsl:variable name="delivery_File"
select="c:/XML/nameOfFile"/>
<xsl:choose>
<!-- we did not find the deliveryFile in this directory -->
<xsl:when test="not($delivery_File)">
............
</xsl:when>
<!-- we find -->
<xsl:otherwise>
...........
</xsl:otherwise>
</xsl:choose>
My procedure XSL never goes in <xsl:otherwise> even if the file exists.
Is it possible with XSL ?
Is anyone knows a solution ?
Thanks in advance
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