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Re: ### Outputting the "full path". Is this possible ?? ###
Is there a way to get the same effect but via a template? Otherwise for each
element from the source document to the destination document I have to
repeat the code. I would have had that if there were an XSLT standard
function, like xsl:path-of.
Khalid
----- Original Message -----
From: "David Carlisle" <davidc@nag.co.uk>
To: <xsl-list@mulberrytech.com>
Sent: Friday, May 26, 2000 10:16 AM
Subject: Re: ### Outputting the "full path". Is this possible ?? ###
> but what if an element contains a sequence of elements, such as
>
> <departments>
> <employees>
> <name>Joe Shmo</name>
> <name>Bob Shmo</name>
> </employees>
> </departments>
>
>
> <xsl:for-each select="(ancestor-or-self::*)"
> >/*[<xsl:value-of
select="1+count(preceding-sibling::*)"/>]</xsl:for-each>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list